compile with g++-4.3

since 4.3 g++ makes sure  the meaning of names isn't changed.

.------------------------------
namespace ns {
    template <typename T>
    struct foo {};

    struct bar
    {
        typedef foo<double> foo;
    };
}
.-----------------------------

will not compile, you have to use explicitd scoping.

.--         typedef foo<double> foo;
++        typedef ns::foo<double> foo;

In case that you use class foo several times like:

.-----------------------------
    struct bar
    {
        foo<int> f;
        typedef ns::foo<double> foo;
    };
.-----------------------------

The code will also not compile, because foo<int> already pulls
ns:foo into the scope of ns::bar. Again you will have to specify
the scope.

.--         foo<int> f;
++         ns::foo<int> f;

[[Imported from SVN: r909]]